9x^2+29x+23=0

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Solution for 9x^2+29x+23=0 equation: 



9x^2+29x+23=0

a = 9; b = 29; c = +23;
Δ = b2-4ac
Δ = 292-4·9·23
Δ = 13
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{13}}{2*9}=\frac{-29-\sqrt{13}}{18}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{13}}{2*9}=\frac{-29+\sqrt{13}}{18}
$

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